Monday, October 24, 2011

Ron Paul Wins Ohio Straw Poll with 54% of TOTAL VOTE!

*Ron Paul Wins Buckeye State Straw Poll with 54% of Total Vote
Republican Presidential Candidate Ron Paul speaks to a gathering of conservative Christians at the Iowa Faith & Freedom Coalition Presidential Forum on October 22, 2011 in Des Moines, Iowa (Scott Olson / Getty Images / AFP)

*Herman Cain 2nd with 26%
*Mitt Romney 3rd with 9%
*Rick Perry and Michelle Bachman both received < 5% of total vote

Are you still a fringe candidate when you pull in more than half of all votes? Just ask Ron Paul.
Even with the establishment cringing at his libertarian leanings and his ideas otherwise radical for a Republican candidate, Congressman Paul received nearly 54 percent of the votes in an Ohio straw poll over the weekend.
The Ohio Republican straw poll was held in the Buckeye State on Saturday, and the majority of the votes cast went to the Texas congressman who continues to show both success and support in his race for the GOP nomination, despite little attention from the mainstream media.
While news outlets have largely focused in recent weeks on the surging popularity of Herman Cain, the pizzaman only raked in nearly half of what Paul got in the straw poll. Following Paul’s first place victory, Cain came in second with around 26 percent of the votes. Former Massachusetts Governor Mitt Romney received around 9 percent, giving him a third place standing. Newt Gingrich, former Speaker of the House, came in fourth.
Rick Perry and Michele Bachmann, both considered top tier candidates earlier in the race, each received less than 5 percent of the vote. In recent weeks their popularity among Republican voters has shown extreme signs of decline.
Paul’s success continues to soar, although he has still not received the same media coverage favored for other Republican hopefuls.
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